**Originally by:** *Psykikk Solette*

so..letīs assume my harvesting cycle (24h) pulls in

900.000 P0(1)

and

855.000 P0(2)

which results in

6000 P1(1)

and

5700 P1(2)

which then results in

712 P2

Is this correct ??

900k / 3k = 300 * 20 P1a (6000)

855k / 3k = 285 * 20 P1b (5700)

a single P0 -> P1 reaction can make 960 units in 24 hours

(2 cycles/hour * 24 hours * 20/cycle). You'll need 5-6 of each P0 -> P1 factory to eat all the units of P0 in 24 hours.

Assuming you have this...

6000 / 40 = 150 * 5 P2

5700 / 40 = 142.5 * 5 P2

A single (P1 + P1) -> P2 reaction can create 120 units in 24 hours (1 cycle/hour * 24 hours * 5/cycle). 142 cycles will yield you with 710 P2, leaving a factory full of P1a, and half a load of P1b. You'll also have a few runs of P1a in the launchpad/silo.

Obviously this assumes your numbers are the "after 24 hours" and have taken into account that that is sustainable. Depletion will reduce yields, and usually shortly after the "halfway" mark of your mining programme (e.g. 12h for a 24h programme, or 2d for a 4d programme)